std::span<T,Extent>:: back
| Sequence | ||||
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(C++11)
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(C++26)
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(C++11)
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| Associative | ||||
| Unordered associative | ||||
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(C++11)
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(C++11)
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(C++11)
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(C++11)
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| Adaptors | ||||
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(C++23)
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(C++23)
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(C++23)
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(C++23)
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| Views | ||||
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(C++20)
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(C++23)
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| Tables | ||||
| Iterator invalidation | ||||
| Member function table | ||||
| Non-member function table |
| Member functions | ||||
| Element access | ||||
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span::back
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(C++26)
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| Iterators | ||||
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(C++23)
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(C++23)
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(C++23)
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(C++23)
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| Observers | ||||
| Subviews | ||||
| Non-member functions | ||||
| Non-member constant | ||||
| Deduction guides |
|
constexpr
reference back
(
)
const
;
|
(since C++20) | |
Returns a reference to the last element in the span.
Calling
back
on an empty span results in undefined behavior.
Parameters
(none)
Return value
A reference to the back element.
Complexity
Constant.
Notes
For a span
c
, the expression
c.
back
(
)
is equivalent to
*
(
c.
end
(
)
-
1
)
.
Example
#include <iostream> #include <span> void print_forward(std::span<const int> const span) { for (auto n{span.size()}; n != 0; --n) std::cout << span.last(n).front() << ' '; std::cout << '\n'; } void print_backward(std::span<const int> const span) { for (auto n{span.size()}; n != 0; --n) std::cout << span.first(n).back() << ' '; std::cout << '\n'; } int main() { constexpr int numbers[]{0, 1, 2, 3, 4}; print_forward(numbers); print_backward(numbers); }
Output:
0 1 2 3 4 4 3 2 1 0
See also
|
access the first element
(public member function) |