std::stack<T,Container>:: emplace

From cppreference.com

template < class ... Args >
void emplace ( Args && ... args ) ;
(since C++11)
(until C++17)
template < class ... Args >
decltype ( auto ) emplace ( Args && ... args ) ;
(since C++17)

Pushes a new element on top of the stack. The element is constructed in-place, i.e. no copy or move operations are performed. The constructor of the element is called with exactly the same arguments as supplied to the function.

Effectively calls c. emplace_back ( std:: forward < Args > ( args ) ... ) ; .

Parameters

args - arguments to forward to the constructor of the element

Return value

(none)

(until C++17)

The value or reference, if any, returned by the above call to Container :: emplace_back .

(since C++17)

Complexity

Identical to the complexity of Container :: emplace_back .

Example

#include <iostream>
#include <stack>
 
struct S
{
    int id;
 
    S(int i, double d, std::string s) : id{i}
    {
        std::cout << "S::S(" << i << ", " << d << ", \"" << s << "\");\n";
    }
};
 
int main()
{
    std::stack<S> stack;
    const S& s = stack.emplace(42, 3.14, "C++"); // for return value C++17 required
    std::cout << "id = " << s.id << '\n';
}

Output:

S::S(42, 3.14, "C++")
id = 42

Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 2783 C++17 emplace returned reference , breaking compatibility with pre-C++17 containers returns decltype(auto)

See also

inserts element at the top
(public member function)
removes the top element
(public member function)