std::experimental::filesystem::path:: compare

From cppreference.com
int compare ( const path & p ) const noexcept ;
(1) (filesystem TS)
int compare ( const string_type & str ) const ;
(2) (filesystem TS)
int compare ( const value_type * s ) const ;
(3) (filesystem TS)

Compares the lexical representations of the path and another path.

1) Returns a value less than, equal to or greater than 0 if the native representation of the path ( native ()) is respectively lexicographically less than, equal to or greater than the native representation of p ( p. native ( ) ). Comparison is performed element-wise, as if by iterating both paths from begin () to end ().
2) Equivalent to compare ( path ( str ) ) .
3) Equivalent to compare ( path ( s ) ) .

Parameters

p - a path to compare to
str - a string representing path to compare to
s - a null-terminated string representing path to compare to

Return value

A value less than 0 if the path is lexicographically less than the given path.

A value equal to 0 if the path is lexicographically equal to the given path.

A value greater than 0 if the path is lexicographically greater than the given path.

Exceptions

2,3) May throw implementation-defined exceptions.

Notes

For two-way comparisons, binary operators may be more suitable.

Example

#include <experimental/filesystem>
#include <iostream>
namespace fs = std::experimental::filesystem;
 
void demo(int rc, fs::path p1, fs::path p2)
{
    if (rc < 0)
        std::cout << p1 << " < " << p2 << '\n';
    else if (rc > 0)
        std::cout << p1 << " > " << p2 << '\n';
    else if (rc == 0)
        std::cout << p1 << " = " << p2 << '\n';
}
 
int main()
{
    fs::path p1 = "/a/b/"; // as if "a/b/." for lexicographical iteration
    fs::path p2 = "/a/b/#";
    demo(p1.compare(p2), p1, p2);
    demo(p1.compare("a/b/_"), p1, "a/b/_");
}

Output:

"/a/b/" > "/a/b/#"
"/a/b/" < "a/b/_"

See also

lexicographically compares two paths
(function)