operator+ (std::move_iterator)

Defined in header <iterator>
template < class Iter > move_iterator < Iter > operator + ( typename move_iterator < Iter > :: difference_type n, const move_iterator < Iter > & it ) ;		(since C++11) (constexpr since C++17) (until C++20)
template < class Iter > constexpr move_iterator < Iter > operator + ( std:: iter_difference_t < Iter > n, const move_iterator < Iter > & it ) ;		(since C++20)

Returns the iterator it incremented by n .

This overload participates in overload resolution only if it. base ( ) + n is well-formed and has type Iter .

(since C++20)

Parameters

n	-	the number of positions to increment the iterator
it	-	the iterator adaptor to increment

Return value

it + n

Example

This section is incomplete Reason: no example

Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR	Applied to	Behavior as published	Correct behavior
LWG 3293	C++20	the non-member operator + was constrained to require it + n is well-formed and has type Iter	changed to it. base ( ) + n

See also

operator++ operator++ (int) operator+= operator+ operator-- operator-- (int) operator-= operator- (C++11)	advances or decrements the iterator (public member function)
operator- (C++11)	computes the distance between two iterator adaptors (function template)