std::ranges::subrange<I,S,K>:: prev

Returns a copy of * this whose begin_ is decremented (or incremented if n is negative). The actual decrement (or increment) operation is performed by advance() . Equivalent to:

auto tmp = * this ;
tmp. advance ( - n ) ;
return tmp ; .

Parameters

Return value

As described above.

Notes

The difference between this function and advance() is that the latter performs the decrement (or increment) in place.

Example

#include <iterator>
#include <list>
#include <print>
#include <ranges>
 
int main()
{
    std::list list{1, 2, 3, 4, 5};
    std::ranges::subrange sub{std::next(list.begin(), 2), std::prev(list.end(), 2)};
    std::println("{} {} {}", sub, sub.prev(), sub.prev(2));
}

[3] [2, 3] [1, 2, 3]

See also