std:: iscntrl (std::locale)
From cppreference.com
C++
Localization library
Character conversions | ||||
String and stream conversions | ||||
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C++11/17/26*
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(
C++11/17/26*
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Text encoding identifications | |||||
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Unicode conversion facets | |||||
(
C++11/17/26*
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(
C++11/17/26*
)
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(
C++11/17/26*
)
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(
C++11/17/26*
)
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Defined in header
<locale>
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template
<
class
CharT
>
bool iscntrl ( CharT ch, const locale & loc ) ; |
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Checks if the given character is classified as a control character by the given locale's std::ctype facet.
Parameters
ch | - | character |
loc | - | locale |
Return value
Returns true if the character is classified as a control character, false otherwise.
Possible implementation
template<class CharT> bool iscntrl(CharT ch, const std::locale& loc) { return std::use_facet<std::ctype<CharT>>(loc).is(std::ctype_base::cntrl, ch); } |
Example
Demonstrates the use of
iscntrl()
with different locales (OS-specific).
Run this code
#include <iostream> #include <locale> int main() { const wchar_t CCH = L'\u0094'; // Destructive Backspace in Unicode std::locale loc1("C"); std::cout << "iscntrl(CCH, C locale) returned " << std::boolalpha << std::iscntrl(CCH, loc1) << '\n'; std::locale loc2("en_US.UTF8"); std::cout << "iscntrl(CCH, Unicode locale) returned " << std::boolalpha << std::iscntrl(CCH, loc2) << '\n'; }
Possible output:
iscntrl(CCH, C locale) returned false iscntrl(CCH, Unicode locale) returned true
See also
checks if a character is a control character
(function) |
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checks if a wide character is a control character
(function) |
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