std::ranges::transform_view<V,F>:: iterator <Const>:: base
From cppreference.com
<
cpp
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ranges
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transform view
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iterator
C++
Ranges library
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Range primitives | |||||||
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Range concepts | |||||||||||||||||||
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Range factories | |||||||||
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Range adaptors | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Helper items | |||||||||||||||||
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std::ranges::transform_view
Member functions | ||||
Deduction guides | ||||
Iterator | ||||
transform_view::
iterator
::base
|
||||
Sentinel | ||||
constexpr
const
ranges::
iterator_t
<
Base
>
&
base
(
)
const
&
noexcept
;
|
(1) | (since C++20) |
constexpr
ranges::
iterator_t
<
Base
>
base
(
)
&&
;
|
(2) | (since C++20) |
Returns the underlying iterator.
1)
Returns a reference to the underlying iterator.
2)
Move constructs the result from the underlying iterator.
Parameters
(none)
Return value
1)
A reference to the underlying iterator.
2)
An iterator move constructed from the underlying iterator.
Example
Run this code
#include <algorithm> #include <iostream> #include <iterator> #include <ranges> int main() { const auto v = { 0, 1, 2, 3, 4 }; auto x2 = [](int x) { return x << 1; }; std::ranges::transform_view tv{ v, x2 }; std::ostream_iterator<int> ostr{ std::cout, " " }; std::ranges::copy(v, ostr), std::cout << '\n'; std::ranges::copy(tv.base(), ostr), std::cout << '\n'; std::ranges::copy(tv, ostr), std::cout << '\n'; }
Output:
0 1 2 3 4 0 1 2 3 4 0 2 4 6 8
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3533 | C++20 |
the
const
&
overload of
base
returns a copy of the underlying iterator
|
returns a reference |
LWG 3593 | C++20 |
the
const
&
overload of
base
might not be noexcept
|
made noexcept |
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