std:: decay

Performs the type conversions equivalent to the ones performed when passing function arguments by value. Formally:

• If T is "array of U " or reference to it, the member typedef type is U* .

• Otherwise, if T is a function type F or reference to one, the member typedef type is std:: add_pointer < F > :: type .

• Otherwise, the member typedef type is std:: remove_cv < std:: remove_reference < T > :: type > :: type .

If the program adds specializations for std::decay , the behavior is undefined.

Member types

Helper types

Possible implementation

template<class T>
struct decay
{
private:
    typedef typename std::remove_reference<T>::type U;
public:
    typedef typename std::conditional< 
        std::is_array<U>::value,
        typename std::add_pointer<typename std::remove_extent<U>::type>::type,
        typename std::conditional< 
            std::is_function<U>::value,
            typename std::add_pointer<U>::type,
            typename std::remove_cv<U>::type
        >::type
    >::type type;
};

Example

#include <type_traits>
 
template<typename T, typename U>
constexpr bool is_decay_equ = std::is_same_v<std::decay_t<T>, U>;
 
int main()
{
    static_assert
    (
        is_decay_equ<int, int> &&
        ! is_decay_equ<int, float> &&
        is_decay_equ<int&, int> &&
        is_decay_equ<int&&, int> &&
        is_decay_equ<const int&, int> &&
        is_decay_equ<int[2], int*> &&
        ! is_decay_equ<int[4][2], int*> &&
        ! is_decay_equ<int[4][2], int**> &&
        is_decay_equ<int[4][2], int(*)[2]> &&
        is_decay_equ<int(int), int(*)(int)>
    );
}

See also