std:: remove_reference

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Defined in header <type_traits>
template < class T >
struct remove_reference ;
(since C++11)

If the type T is a reference type, provides the member typedef type which is the type referred to by T . Otherwise type is T .

If the program adds specializations for std::remove_reference , the behavior is undefined.

Member types

Name Definition
type the type referred by T or T if it is not a reference

Helper types

template < class T >
using remove_reference_t = typename remove_reference < T > :: type ;
(since C++14)

Possible implementation 

template<class T> struct remove_reference { typedef T type; };
template<class T> struct remove_reference<T&> { typedef T type; };
template<class T> struct remove_reference<T&&> { typedef T type; };

Example

Run this code 
#include <iostream>
#include <type_traits>
 
int main()
{
    std::cout << std::boolalpha;
 
    std::cout << "std::remove_reference<int>::type is int? "
              << std::is_same<int, std::remove_reference<int>::type>::value << '\n';
    std::cout << "std::remove_reference<int&>::type is int? "
              << std::is_same<int, std::remove_reference<int&>::type>::value << '\n';
    std::cout << "std::remove_reference<int&&>::type is int? "
              << std::is_same<int, std::remove_reference<int&&>::type>::value << '\n';
    std::cout << "std::remove_reference<const int&>::type is const int? "
              << std::is_same<const int,
                              std::remove_reference<const int&>::type>::value << '\n';
}

Output: 

std::remove_reference<int>::type is int? true
std::remove_reference<int&>::type is int? true
std::remove_reference<int&&>::type is int? true
std::remove_reference<const int&>::type is const int? true

See also

(C++11)
checks if a type is either an lvalue reference or rvalue reference
(class template)
(C++11) (C++11)
adds an lvalue or rvalue reference to the given type
(class template)
(C++20)
combines std::remove_cv and std::remove_reference
(class template)
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