std:: declval

From cppreference.com
Utilities library
General utilities
Relational operators (deprecated in C++20)
Defined in header <utility>
template < class T >
typename std:: add_rvalue_reference < T > :: type declval ( ) noexcept ;
(since C++11)
(until C++14)
(unevaluated-only)
template < class T >
std:: add_rvalue_reference_t < T > declval ( ) noexcept ;
(since C++14)
(unevaluated-only)

Helper template for writing expressions that appear in unevaluated contexts , typically the operand of decltype . In unevaluated context, this helper template converts any type T (which may be an incomplete type) to an expression of that type, making it possible to use member functions of T without the need to go through constructors.

std::declval can only be used in unevaluated contexts and is not required to be defined; it is an error to evaluate an expression that contains this function. Formally, the program is ill-formed if this function is odr-used .

Parameters

(none)

Return value

Cannot be evaluated and thus never returns a value. The return type is T&& (reference collapsing rules apply) unless T is (possibly cv-qualified) void , in which case the return type is T .

Notes

std::declval is commonly used in templates where acceptable template parameters may have no constructor in common, but have the same member function whose return type is needed.

Possible implementation

template<typename T>
typename std::add_rvalue_reference<T>::type declval() noexcept
{
    static_assert(false, "declval not allowed in an evaluated context");
}

Example

#include <iostream>
#include <utility>
 
struct Default
{
    int foo() const { return 1; }
};
 
struct NonDefault
{
    NonDefault() = delete;
    int foo() const { return 1; }
};
 
int main()
{
    decltype(Default().foo())               n1 = 1;     // type of n1 is int
    decltype(std::declval<Default>().foo()) n2 = 1;     // same
 
//  decltype(NonDefault().foo())               n3 = n1; // error: no default constructor
    decltype(std::declval<NonDefault>().foo()) n3 = n1; // type of n3 is int
 
    std::cout << "n1 = " << n1 << '\n'
              << "n2 = " << n2 << '\n'
              << "n3 = " << n3 << '\n';
}

Output:

n1 = 1
n2 = 1
n3 = 1

See also

decltype specifier (C++11) obtains the type of an expression or an entity
(C++11) (removed in C++20) (C++17)
deduces the result type of invoking a callable object with a set of arguments
(class template)