std::chrono::weekday_last:: weekday_last

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std::chrono::weekday_last
constexpr explicit weekday_last ( const std:: chrono :: weekday & wd ) noexcept ;
(since C++20)

Constructs a weekday_last object storing the weekday wd .

Notes

A more convenient way to construct a weekday_last is with weekday 's operator [ ] , i.e., wd [ std:: chrono :: last ] .

Example

Run this code 
#include <chrono>
#include <iostream>
using namespace std::chrono;
 
int main()
{
    const year_month_day ymd{floor<days>(system_clock::now())};
    const weekday_last wdl{Sunday[last]}; // A last Sunday of a month
    const year_month_day last_sun{ymd.year() / ymd.month() / wdl};
 
    std::cout << "The last Sunday of current month falls on "
              << (int)last_sun.year() << '/'
              << (unsigned)last_sun.month() << '/'
              << (unsigned)last_sun.day() << '\n';
}

Possible output: 

The last Sunday of current month falls on 2021/9/26
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