std:: make_any
From cppreference.com
C++
Utilities library
|
|
Defined in header
<any>
|
||
template
<
class
T,
class
...
Args
>
std:: any make_any ( Args && ... args ) ; |
(1) | (since C++17) |
template
<
class
T,
class
U,
class
...
Args
>
std:: any make_any ( std:: initializer_list < U > il, Args && ... args ) ; |
(2) | (since C++17) |
Constructs an
any
object containing an object of type
T
, passing the provided arguments to
T
's constructor.
1)
Equivalent to
return
std::
any
(
std::
in_place_type
<
T
>
,
std::
forward
<
Args
>
(
args
)
...
)
;
2)
Equivalent to
return
std::
any
(
std::
in_place_type
<
T
>
, il,
std::
forward
<
Args
>
(
args
)
...
)
;
Example
Run this code
#include <any> #include <complex> #include <functional> #include <iostream> #include <string> int main() { auto a0 = std::make_any<std::string>("Hello, std::any!\n"); auto a1 = std::make_any<std::complex<double>>(0.1, 2.3); std::cout << std::any_cast<std::string&>(a0); std::cout << std::any_cast<std::complex<double>&>(a1) << '\n'; using lambda = std::function<void(void)>; // Put a lambda into std::any. Attempt #1 (failed). std::any a2 = [] { std::cout << "Lambda #1.\n"; }; std::cout << "a2.type() = \"" << a2.type().name() << "\"\n"; // any_cast casts to <void(void)> but actual type is not // a std::function..., but ~ main::{lambda()#1}, and it is // unique for each lambda. So, this throws... try { std::any_cast<lambda>(a2)(); } catch (std::bad_any_cast const& ex) { std::cout << ex.what() << '\n'; } // Put a lambda into std::any. Attempt #2 (successful). auto a3 = std::make_any<lambda>([] { std::cout << "Lambda #2.\n"; }); std::cout << "a3.type() = \"" << a3.type().name() << "\"\n"; std::any_cast<lambda>(a3)(); }
Possible output:
Hello, std::any! (0.1,2.3) a2.type() = "Z4mainEUlvE_" bad any_cast a3.type() = "St8functionIFvvEE" Lambda #2.
See also
constructs an
any
object
(public member function) |
|
(C++17)
|
type-safe access to the contained object
(function template) |
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