std:: common_type <std::chrono::duration>

From cppreference.com
Utilities library
General utilities
Relational operators (deprecated in C++20)
Defined in header <chrono>
template < class Rep1, class Period1, class Rep2, class Period2 >

struct common_type < std:: chrono :: duration < Rep1, Period1 > ,

std:: chrono :: duration < Rep2, Period2 >> ;
(since C++11)

Exposes the type named type , which is the common type of two std::chrono::duration s, whose period is the greatest common divisor of Period1 and Period2 .

Member types

Member type Definition
type std:: chrono :: duration < typename std:: common_type < Rep1, Rep2 > :: type , /* see note */ >

Note

The period of the resulting duration can be computed by forming a ratio of the greatest common divisor of Period1 :: num and Period2 :: num and the least common multiple of Period1 :: den and Period2 :: den .

Example

#include <chrono>
#include <iostream>
#include <type_traits>
 
// std::chrono already finds the greatest common divisor,
// likely using std::common_type<>. We make the type
// deduction externally. 
 
template<typename T,typename S>
constexpr auto durationDiff(const T& t, const S& s)
    -> typename std::common_type<T,S>::type
{
    typedef typename std::common_type<T,S>::type Common;
    return Common(t) - Common(s);
}
 
int main() 
{
    using namespace std::literals;
 
    constexpr auto ms = 30ms;
    constexpr auto us = 1100us;
    constexpr auto diff = durationDiff(ms, us);
 
    std::cout << ms << " - " << us << " = " << diff << '\n';
}

Output:

30ms - 1100us = 28900us

See also

specializes the std::common_type trait
(class template specialization)
determines the common type of a group of types
(class template)