std::literals::chrono_literals:: operator""ms

Forms a std::chrono::duration literal representing milliseconds.

Parameters

Return value

The std::chrono::duration literal.

Possible implementation

constexpr std::chrono::milliseconds operator""ms(unsigned long long ms)
{
    return std::chrono::milliseconds(ms);
}
constexpr std::chrono::duration<long double, std::milli> operator""ms(long double ms)
{
    return std::chrono::duration<long double, std::milli>(ms);
}

Notes

This operator is declared in the namespace std :: literals :: chrono_literals , where both literals and chrono_literals are inline namespaces . Access to this operator can be gained with:

• using namespace std :: literals ,
• using namespace std :: chrono_literals , or
• using namespace std :: literals :: chrono_literals .

In addition, within the namespace std :: chrono , the directive using namespace literals :: chrono_literals ; is provided by the standard library , so that if a programmer uses using namespace std :: chrono ; to gain access to the classes in the chrono library , the corresponding literal operators become visible as well.

Example

#include <chrono>
#include <iostream>
 
int main()
{
    using namespace std::chrono_literals;
    constexpr auto d1{250ms};
    constexpr std::chrono::milliseconds d2{1s};
    std::cout << d1 << " = " << d1.count() << " milliseconds\n"
              << d2 << " = " << d2.count() << " milliseconds\n";
}

250ms = 250 milliseconds
1000ms = 1000 milliseconds

See also