std:: _Exit

Causes normal program termination to occur without completely cleaning the resources.

Destructors of variables with automatic, thread local and static storage durations are not called. Functions passed to std::at_quick_exit() or std::atexit() are not called. Whether open resources such as files are closed is implementation defined.

If exit_code is 0 or EXIT_SUCCESS , an implementation-defined status indicating successful termination is returned to the host environment. If exit_code is EXIT_FAILURE , an implementation-defined status, indicating unsuccessful termination, is returned. In other cases implementation-defined status value is returned.

Parameters

Return value

(none)

Example

#include <iostream>
 
class Static
{
public:
    ~Static() 
    {
        std::cout << "Static dtor\n";
    }
};
 
class Local
{
public:
    ~Local() 
    {
        std::cout << "Local dtor\n";
    }
};
 
Static static_variable; // dtor of this object will *not* be called
 
void atexit_handler()
{
    std::cout << "atexit handler\n";
}
 
int main()
{
    Local local_variable; // dtor of this object will *not* be called
 
    // handler will *not* be called
    const int result = std::atexit(atexit_handler);
 
    if (result != 0)
    {
        std::cerr << "atexit registration failed\n";
        return EXIT_FAILURE;
    }
 
    std::cout << "test" << std::endl; // flush from std::endl
        // needs to be here, otherwise nothing will be printed
    std::_Exit(EXIT_FAILURE);
}

test

See also