std::shared_ptr<T>:: operator*, std::shared_ptr<T>:: operator->

Dereferences the stored pointer. The behavior is undefined if the stored pointer is null.

Parameters

(none)

Return value

Remarks

When T is an array type or (possibly cv-qualified) (since C++17) void , it is unspecified whether function (1) is declared. If it is declared, it is unspecified what its return type is, except that the declaration (although not necessarily the definition) of the function shall be well formed. This makes it possible to instantiate std:: shared_ptr < void >

Example

#include <iostream>
#include <memory>
 
struct Foo
{
    Foo(int in) : a(in) {}
    void print() const
    {
        std::cout << "a = " << a << '\n';
    }
    int a;
};
 
int main()
{
    auto ptr = std::make_shared<Foo>(10);
    ptr->print();
    (*ptr).print();
}

a = 10
a = 10

See also